Cartesian to Polar coordinates To convert from Cartesian to polar coordinates, we use the following identities r2 = x2 + y2; tan = y x When choosing the value of , we must be careful to consider which quadrant the point is in, since for any given number a, there are two angles with tan = a, in the interval 0 2?. This couple of Matlab functions perform a coordinate conversion of a point given in Cartesian coordinates to polar coordinates, and vice versa. When we use this polar-to-cartesian function, we enter a magnitude and an angle in degrees as parameters. The function returns a real number (x) and a complex number (y value). For example, if you want to reference the image A that Matt mentioned to the default (Intrinsic) coordinate system used by MATLAB in which the center of the first pixel is located at position (1,1) and each pixel has an extent of one unit, you could use the following syntax of imref2d: To convert from polar co-ordinates to Cartesian co-ordinates, use the equations x = rcos?, y = rsin?. To convert from Cartesian co-ordinates to polar co-ordinates, use the equations r 2= x +y , tan? = y x. If the point is not in the ?rst quadrant then you should ?nd an acute angle ? using a right- Matlab Tutorial. The basics. Write a function that find the volume of a 3D rectangle in Matlab Scalar functions in Matlab: e Matlab, Cosine function and more Left division vs Right Matrix division - Matlab Convert numbers from Polar to Cartesian and vice versa. Plotting. Plotting in Matlab pol2cart. Transform polar or cylindrical coordinates to Cartesian. Syntax [X,Y] = pol2cart(THETA,RHO) [X,Y,Z] = pol2cart(THETA,RHO,Z) Description [X,Y] = pol2cart(THETA,RHO) transforms the polar coordinate data stored in corresponding elements of THETA and RHO to two-dimensional Cartesian, or xy, coordinates. How to convert Polar (R and Theta) coordinates to Cartesian (x,y) coordinates. Purpose of use Locating points on a circle in an image space. Comment/Request Requires lots of manual translation for this use - 0,0 is top left of an image, rather than the center :) and also thus Y increases going down.